The sum of all natural [positive whole] numbers 1 to 100 can be calculated using the formula, S = n/2 × [2a + (n − 1) × d], where n is the total number of natural numbers from 1 to 100, d is the difference between the two consecutive terms, and a is the first term. There are a total of 100 natural numbers, so n = 100.

Thus, a = 1, d = 1, and n = 100.

Let's calculate the sum of the natural numbers 1 to 100.

Use the formula.

S = n/2 × [2a + (n − 1) × d]

S = 100/2 × [2 + (100 – 1) × 1]

S = 50 × [2 + 99]

Isn’t that answer interesting?

Thus, a = 1, d = 1, and n = 100.

Let's calculate the sum of the natural numbers 1 to 100.

Use the formula.

S = n/2 × [2a + (n − 1) × d]

S = 100/2 × [2 + (100 – 1) × 1]

S = 50 × [2 + 99]

**S = 5050**Isn’t that answer interesting?