Alexander, nine, and I had a dispute over a combinations problem. In fact, we were both wrong. I went home and checked my sources.
Combinations There are 91 elements to choose from, and 4 elements are chosen. In English, if you have 91 students and choose four at a time, how many combinations are there? Calculation: Formula n!/k!(n−k)! Two examples of a factorial: 91! = 91x90x89x88… (and so on) 4! = 4x3x2x1 Where n = 91 and k = 4 C₄(91) = (91/4) = (91!/4!(91−4)! = 91x90x89x88/4x3x2x1 = 2672670 The number of combinations is 2,672,670.
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